J(x)=x^2-8x+16

Solution for J(x)=x^2-8x+16 equation:

(J)=J^2-8J+16

We move all terms to the left:

(J)-(J^2-8J+16)=0

We get rid of parentheses

-J^2+J+8J-16=0

We add all the numbers together, and all the variables

-1J^2+9J-16=0

a = -1; b = 9; c = -16;
Δ = b2-4ac
Δ = 92-4·(-1)·(-16)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$J_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$J_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$J_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{17}}{2*-1}=\frac{-9-\sqrt{17}}{-2}
$
$J_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{17}}{2*-1}=\frac{-9+\sqrt{17}}{-2}
$